How Aristarchus found moon's diameter?

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Discussion Overview

The discussion revolves around Aristarchus's method for estimating the diameter of the Moon in relation to the Earth. Participants explore the calculations and assumptions made by Aristarchus, questioning the accuracy of his results and the methodology he employed.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants inquire about the specific calculations Aristarchus used to derive that the Earth's diameter is 2.5 times that of the Moon's diameter.
  • There are questions regarding the assumptions made in the calculations, particularly concerning the values of angles and distances.
  • One participant mentions the potential errors in Aristarchus's calculations, specifically regarding the values for x and θ, and references Archimedes's commentary on Aristarchus's work.
  • Some participants express a need for clearer explanations and diagrams to understand the mathematical relationships involved.
  • There is a suggestion to look at external resources, such as Wikipedia and videos, although some participants find these resources lacking in clarity.
  • One participant emphasizes the importance of understanding similar triangles in relation to Aristarchus's method.
  • Another participant reflects on the impressive nature of ancient astronomical measurements despite the limitations of their tools.

Areas of Agreement / Disagreement

The discussion contains multiple competing views regarding the accuracy of Aristarchus's calculations and the interpretation of his methodology. Participants express uncertainty about specific values and the implications of those values on the results.

Contextual Notes

Participants note that the discussion involves unresolved mathematical steps and differing interpretations of Aristarchus's statements, particularly concerning the meaning of "meros" in the context of angular measurements.

prashant singh
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how aristarchus found that Earth's diameter = 2.5 × moon's diameter . What wrong things he did to calculate the size of moon just like the shodow part.
 
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prashant singh said:
how aristarchus found that Earth's diameter = 2.5 × moon's diameter . What wrong things he did to calculate the size of moon just like the shodow part.
You could look him up on the Internet. There are several fine articles there which discuss Aristarchus and his work. :smile:
 
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Mathematical parts and diagrams
 
Yes I have tried wikipidia, it didnt helped me , there was only one image and equations , I need some brief explanation .
 
Well, that's exactly what you asked for earlier... Did you scroll down to the "Illustrations" section and check out the links to the interactive illustrations? Or check out the references for the page? I found this video as a reference for the article which supposedly explains the method, but I do not speak whatever language is being spoken in the video.
 
I want to know why they took (L/S) = (l/s) and how they got (L/t) =(l/t)(180/(pi × theta) and what is theta here
 
prashant singh said:
I want to know why they took (L/S) = (l/s) and how they got (L/t) =(l/t)(180/(pi × theta) and what is theta here

I'd have to work through the whole process to understand it and I don't have time for that right now. Sorry.
Until then, I'd recommend looking up what similar triangles mean and carefully working your way through the process as best you can (if you haven't done so already).
 
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Can u explain me only first part please.
 
  • #10
prashant singh said:
Can u explain me only first part please.
Similar triangles?
PF will respond so much better when you appear to have put some effort in, yourself.
What have you actually learned from that Wiki article?
I have spent less than five minutes on the recommended Wiki article and I found:
"The error in this calculation comes primarily from the poor values for x and θ. The poor value for θ is especially surprising, since Archimedes writes that Aristarchus was the first to determine that the Sun and Moon had an apparent diameter of half a degree. This would give a value of θ = 0.25, and a corresponding distance to the moon of 80 Earth radii, a much better estimate. The disagreement of the work with Archimedes seems to be due to its taking an Aristarchos statement that the lunisolar diameter is 1/15 of a "meros" of the zodiac to mean 1/15 of a zodiacal sign (30°), unaware that the Greek word "meros" meant either "portion" or 7°1/2; and 1/15 of the latter amount is 1°/2, in agreement with Archimedes' testimony."

Is this a homework assignment?
 
  • #11
No its not a H.W problem but thanks for explaining
sophiecentaur said:
Similar triangles?
PF will respond so much better when you appear to have put some effort in, yourself.
What have you actually learned from that Wiki article?
I have spent less than five minutes on the recommended Wiki article and I found:
"The error in this calculation comes primarily from the poor values for x and θ. The poor value for θ is especially surprising, since Archimedes writes that Aristarchus was the first to determine that the Sun and Moon had an apparent diameter of half a degree. This would give a value of θ = 0.25, and a corresponding distance to the moon of 80 Earth radii, a much better estimate. The disagreement of the work with Archimedes seems to be due to its taking an Aristarchos statement that the lunisolar diameter is 1/15 of a "meros" of the zodiac to mean 1/15 of a zodiacal sign (30°), unaware that the Greek word "meros" meant either "portion" or 7°1/2; and 1/15 of the latter amount is 1°/2, in agreement with Archimedes' testimony."

Is this a homework assignment?
 
  • #12
prashant singh said:
No its not a H.W problem but thanks for explaining
Ouch. That was hardly an explanation - not one that could satisfy me, in any event.
But you really have to hand it to those ancients who managed to measure some of those astronomical angles and distances a lot better than you or I would do, using tools from our shed and some bits of good quality timber!
 
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