How can 1/y = kr + C/e^(rt) be solved for y?

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SUMMARY

The equation 1/y = kr + C/e^(rt) cannot be rearranged to y = 1/kr + e^(rt)/C. The correct approach to solving for y involves recognizing that 1/a = b + c translates to a = 1/(b+c), not to the sum of the reciprocals. This fundamental misunderstanding of algebraic manipulation is clarified through the example of 3 = 2 + 1, which does not imply that 1/3 equals 1/2 + 1/1.

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Homework Statement



1/y = kr + C/e^(rt)

Is this equal to y = 1/kr + e^(rt)/C

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Homework Equations





The Attempt at a Solution

 
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No, 1/a = b + c is not a = 1/b + 1/c but rather a = 1/(b+c)

Think about it this way 3 = 2 + 1 but would you say that 1/3 = 1/2 + 1/1?
 

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