Maxwell Equations and Fourier Expansions

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Homework Statement



The field E(r,t) can be written as a Fourier expansion of plane waves [tex]E(r,t)=∫E(k,w)e^{i(kr-wt)}d^{3}kdw[/tex] with similar expansions for other fields.

Need to show the derivation of [tex]kXE(k,w)=wB(k,w)[/tex] from Faraday's law [tex]∇XE(r,t)=-∂B(r,t)/∂t[/tex] and also the derivation of [tex]kXH(k,w)=-wD(k,w)[/tex] from Ampere's law [tex]∇XH(r,t)=∂D(r,t)/∂t[/tex]

Homework Equations



[tex]∫e^{ax}=(1/a)e^{ax}[/tex]

The Attempt at a Solution



I thought the Fourier expansion expression for E meant to integrate with once with respect to w and three times with respect to k, so get:

[tex]∫E(k,w)e^{i(kr-wt)}d^{3}kdw = (1/r)x(1/r)x(1/r)x(-1/t)e^{i(kr-wt)}=(-1/r^{3}t)e^{i(kr-wt)}[/tex]

But that clearly doesn't give the result, no k or w there at all... what am I doing wrong? I get this isn't tricky but can't figure it out.
 
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Just try to evaluate curlE : (curlE)i = εijkjEk and compare the result with the definition of cross product : (A×B)i = εijkΑjBk. You don't have to try to evaluate the Fourier integral; actually you can't, since E(k,w) is unknown (if known, then the field E(r,t) would also be known). Make the partial derivations of the Fourier integral by derivating directly the integrand.
 
I still don't get how to do this :frown:

So I should take [tex](∇E)i = ε_{ijk}∂_{j}E_{k}[/tex] and compare the result with the definition of cross product [tex](A×B)i = ε_{ijk}Α_{j}B_{k}[/tex]?

So [tex](∇E) = ∂_{j}E_{k} = A_{j}B_{k}=AXB=kXE[/tex]?