laplacianZero
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[(x)*(1/9)^(1/9)^x ] - 1 = y
How do you find the roots?
How do you find the roots?
The discussion revolves around finding the roots of the equation (x)*(1/9)^(1/9)^x - 1 = y using the DESMOS graphing calculator. Participants explore various methods for identifying roots, including numerical approximation and graphical analysis.
Participants express varying opinions on the methods for finding roots, with some favoring graphical approaches and others suggesting numerical methods or the Lambert W function. There is no consensus on the exact roots or the best approach to take.
Participants note limitations in their ability to reproduce results and the potential for misinterpretation of the equation's structure, particularly regarding exponentiation. The discussion reflects uncertainty about the behavior of the function and the accuracy of the roots identified.
This discussion may be of interest to those exploring numerical methods for root-finding, users of graphing calculators like DESMOS, and individuals studying the properties of equations involving exponentiation.
Since x appears as both the base and as an exponent, the only non-graphical, non-numerical alternative is the Lambert W function. See https://en.wikipedia.org/wiki/Lambert_W_functionlaplacianZero said:Besides plotting to find approximate root or using the Newton raphson method, are there any other ways?
The expression does not have a second zero, at least not with the conventional interpretation of a^b^c as a^(b^c).jedishrfu said:The desmos graph calculator shows two zeros at ? and at ? where ## 0 < x < 10##
The ? are left to the student.
Yes, that may have what happened and I didn't notice. I should have saved the expression that was input then I didn't where I went wrong.mfb said:You get that if you interpret a^b^c as (a^b)^c = a^(b*c).