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bcm322
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Find the equation of the line through (-9, 2); perpendicular to y= -1.
Use standard form : y=mx+b
Use standard form : y=mx+b
bcm322 said:Find the equation of the line through (-9, 2); perpendicular to y= -1.
Use standard form : y=mx+b
Olinguito said:Did you make a typo? Perhaps you mean the line $\color{black}y=\color{red}x\color{black}-1$, or something like that?
The answer to the problem as you type it cannot be put the standard form $y=mx+b$.
The formula for finding the equation of a line is y = mx + b, where m is the slope of the line and b is the y-intercept.
The slope of a line can be found by using the formula (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are any two points on the line.
A perpendicular line is a line that intersects another line at a 90-degree angle. This means that the slopes of the two lines are negative reciprocals of each other.
To find the equation of a line perpendicular to a given line, you can use the formula y = -1/mx + b, where m is the slope of the given line and b is the y-intercept of the new line.
Yes, for example, if the given line is y = -2x + 3, the slope is -2. And to find the equation of a line perpendicular to this, we would use the formula y = -1/-2x + b, which simplifies to y = 1/2x + b. Then, using the coordinates (-9, 2), we can plug in the values to find the y-intercept (b) and obtain the equation y = 1/2x + 5/2.