How can I find the equation of a line perpendicular to a plane in 3D?

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SUMMARY

To find the equation of a line perpendicular to a plane in 3D, one must first determine the normal vector of the plane formed by three points A(x1, y1, z1), B(x2, y2, z2), and C(x3, y3, z3). This is achieved using the cross product of the vectors AB and AC. The line's equation can then be expressed in Cartesian form, passing through point A and aligned with the normal vector of the plane.

PREREQUISITES
  • Understanding of 3D Cartesian coordinates
  • Knowledge of vector operations, specifically cross products
  • Familiarity with the concept of normal vectors in geometry
  • Ability to express equations in Cartesian form in \mathbb{R}^3
NEXT STEPS
  • Study the properties of normal vectors in 3D geometry
  • Learn how to compute cross products of vectors
  • Explore the Cartesian equation of a line in three-dimensional space
  • Practice solving problems involving planes and lines in 3D
USEFUL FOR

Students studying geometry, particularly those tackling 3D vector problems, as well as educators looking for clear explanations of line and plane relationships in three-dimensional space.

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Homework Statement


How would I find the equation of a line which passes through A(x1, y1, z1) and is perpendicular to A(x1, y1, z1) B(x2, y2, z2), C(x3, y3, z3)

Homework Equations


Cartesian form of a line in [tex]\mathbb{R}^3[/tex]

The Attempt at a Solution


Not sure if this is right but would finding the equation of the plane which contains all three points and then finding the equation of the line that passes through A and that plane be correct?
 
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Yes, but your line needs to be [as you say] perpendicular to the plane, which is equivalent to being parallel to the normal to the plane.

If you don't really care about the plane, you have enough information for find a normal-vector to the plane... by using cross-products.
 

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