The discussion revolves around simplifying the expression \( \frac{1}{\frac{1}{a}} - \frac{1}{b} \) and understanding the requirements for adding fractions. The subject area pertains to algebra and precalculus concepts.
The discussion is ongoing, with participants providing guidance on how to approach the problem. There are multiple interpretations of the expression being simplified, and some participants are confirming their understanding of the process without reaching a definitive conclusion.
Participants note constraints such as the conditions that \( a \) and \( b \) cannot equal zero and that \( a \) cannot equal \( b \). There is also a suggestion to post in a different section for better context.
I'm not going to do it for you.boricua_2004 said:is that wat you think it is or the answer and how did you get there and from my answer choices that's not one them
Good!boricua_2004 said:ok i have this so far a-1/b I am i in the right path
Yep. So a's denominator is just 1, so 1/b determines the denominator needed.boricua_2004 said:a denominator if I am correct
So what do you get?boricua_2004 said:multiply by b
No, you're only multiplying a by b and writing all of the numerator under a common denominator, b.boricua_2004 said:because if i multiply by b the b cancels in the denominator and then its a-b or b-a right
Be careful with how you write or type it.boricua_2004 said:so it should equal ab-1/b