How Can I Prove Continuity Using Epsilon Delta Definition?

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SUMMARY

The discussion centers on the epsilon-delta definition of continuity in advanced calculus, specifically regarding the assumption that delta can be less than 1. Participants confirm that if |x-y| < min(delta, 1), then |x-y| < delta holds true, allowing for the simplification of proofs. An example provided is the function x^4, which satisfies the epsilon-delta condition under this assumption. This approach is valid as it focuses on an arbitrarily small neighborhood around the point of interest.

PREREQUISITES
  • Epsilon-delta definition of continuity
  • Understanding of limits in calculus
  • Basic knowledge of polynomial functions
  • Familiarity with mathematical proofs
NEXT STEPS
  • Study the epsilon-delta definition of continuity in detail
  • Explore proofs involving polynomial functions like x^4
  • Learn about the implications of choosing different delta values in proofs
  • Review resources on limit definitions in calculus
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Students in advanced calculus, mathematics educators, and anyone seeking to deepen their understanding of continuity and limit proofs using the epsilon-delta framework.

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Recently in adv calc we have been dealing with the epsilon delta definition for continuity, and my professor said that it is ok to assume that delta<1. I actually used this to show that x^4 satisfies the epsilon delta condition but I'm not quite sure why we can take delta<1. I am sure you guys know the definition and it doesn't restrict delta at all.

I'm hoping someone can refer me to a resource or just give me some kind of insight.

Thanks
 
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Well, it rests on the simple fact that if |x-y|<min(delta,1), then |x-y|<delta.
 
Because you only care about it in some arbitrarily small neighborhood.

You could assume delta < .1 and base a proof off it.
 

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