How Can I Reduce Voltage from 1.3V-4.8V to Below 1.15V for My Microprocessor?

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Homework Help Overview

The discussion revolves around reducing a varying input voltage from a range of 1.3V to 4.8V to below 1.15V for a microprocessor that registers high above this threshold. The original poster describes the challenge of ensuring the microprocessor functions correctly by achieving a lower voltage level.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various methods for reducing voltage, including the use of a potential divider and diodes. Questions arise regarding the effectiveness of these methods and their impact on the counting process.

Discussion Status

Some participants suggest using a voltage divider as a potential solution, while others express concerns about the implications for the counting process and the need for appropriate resistor selection. There is an ongoing exploration of different approaches without a clear consensus on the best method.

Contextual Notes

Participants note that the original poster has already attempted certain methods, such as using a diode and resistors, which did not yield the desired results. There is an emphasis on ensuring that the current drawn from the source remains within specifications.

rollyasilo
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i have a module with microprocessor of 1.15volt sense level. when the potential is above this value it registers high and below it registers low. however the potential from the source varies from 1.3volts to 4.8volts only.nothing less than 1.15volts so all registers are high.

anybody can help me reduced the lowest potential to be less than 1.15volts so this device will work. i used this device for pulse counting from a solid state digital output.

any idea?

rolly
 
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A simpler method may be to reduce the input voltage by using a potential divider. Or would that interfere with your counting process?

~H
 
Last edited:
I have tried with diode 1N40001 to reduced the lowest and highest potential by 0.7volt but it did'nt work at all. I've tried with resistor but it reduced the higher potential only and lowest potential still the same.

anybody can help me resolved this matter.

rolly
 
rollyasilo said:
I've tried with resistor but it reduced the higher potential only and lowest potential still the same.

I thought you needed only a potential difference of 1.15 V ?
 
A voltage divider might do the trick as Hootenanny suggest. You need to select resitors [itex]R1, R2[/itex] such that the current drawn from the source, [itex]I[/itex], is appropiate to its specs (too small a series resistance will drain the source).
[tex]I=\frac{V_{in}}{R1+R2}[/tex]
The output voltage will then be
[tex]V_{out}=I R2[/tex]
resulting in
[tex]V_{out}=\frac{R2}{R1+R2}V_{in}[/tex]

Note that the effective [itex]R2[/itex] resistance might be altered by connecting your module to the voltage divider circuit.
 
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