Let the Wronskian between the functions f and g to be 3e[itex]^{4t}[/itex], if f(t) = e[itex]^{2t}[/itex], then what is g(t)?(adsbygoogle = window.adsbygoogle || []).push({});

So the Wronskian setup is pretty easy

W(t) = fg' - f'g = 3e[itex]^{4t}[/itex]

f = e[itex]^{2t}[/itex]

f' = 2e[itex]^{2t}[/itex]

So plugging it in I would get:

e[itex]^{2t}[/itex]g' - 2e[itex]^{2t}[/itex]g = 3e[itex]^{4t}[/itex]

Which results in

g' - 2g = 3e[itex]^{2t}[/itex]

How can I solve for g without using integrating factor? Is it even possible? Thanks :)

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# How can I solve this without using integrating factor?

**Physics Forums | Science Articles, Homework Help, Discussion**