Using an integrating factor properly

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SUMMARY

The discussion focuses on solving the differential equation dy/dt - 2y = 4 - t using an integrating factor, specifically e^(-2t). The user initially struggles with the integration process after applying the integrating factor. A key simplification occurs when applying the product rule, leading to the expression d(ye^(-2t))/dt = 4e^(-2t) - te^(-2t). This transformation is crucial for correctly solving the differential equation.

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  • Understanding of first-order linear differential equations
  • Familiarity with integrating factors in differential equations
  • Knowledge of the product rule in calculus
  • Basic skills in manipulating exponential functions
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  • Learn about the product rule and its applications in calculus
  • Practice solving first-order linear differential equations
  • Explore advanced techniques for simplifying differential equations
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Students and educators in mathematics, particularly those focusing on differential equations, as well as anyone looking to enhance their calculus skills.

cameuth
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alright guys, I've been trying to tackle this for a couple of hours now.

dy/dt-2y=4-t
my integrating factor is e^(-2t) of course.

dy(e^(-2t))/dt-2ye^(-2t)=4e^(-2t)-te^(-2t)

then I get completely lost. how do I integrate when it's like this? My book simplifies the above equation into

d(e^(-2y))/dt=4e^(-2t)-te^(-2t)

can anyone explain how that simplification occurs??
 
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hi cameuth! :smile:

(try using the X2 button just above the Reply box :wink:)
cameuth said:
d(e^(-2y))/dt=4e^(-2t)-te^(-2t)

can anyone explain how that simplification occurs??

(you mean d(ye-2t)/dt :wink:)

use the product rule on ye-2t :smile:
 

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