Find g(t) Given Wronskian and f(t)=e2t

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The discussion centers on finding the function g(t) given the Wronskian W of f and g as 3e4t and f(t) = e2t. The derived equation is g'(t) - 2g(t) = 3e2t, which is a linear differential equation. The integrating factor used is e-2t, allowing for the solution of g(t) through standard methods for linear differential equations. The participants confirm the approach and express confidence in the solution process.

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  • Understanding of Wronskian in differential equations
  • Familiarity with linear differential equations
  • Knowledge of integrating factors
  • Basic calculus, specifically differentiation and integration
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If the Wronskian W of f and g is 3e4t, and if f(t)=e2t, find g(t).

Here's the work:
e2tg'(t)-(e2t)'g(t)=3e4t
e2tg'(t)-2e2tg(t)=3e4t
g'(t)-2g(t)=3e2t
p=-2
e^integral of p=e-2t
g(t)=?
 
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I think you should leave the posting template, it's listed in the rules of the forum.

But anyways, it looks like you've shown that g(t) satisfies a linear differential equation. It also looks like you've listed an integrating factor of e^(∫-2 dt).

So, you're pretty much done. Do you know how to apply an integrating factor to solve a linear differential equation?
 
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Thanks, I've already solved it.
 

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