MHB How can inverse functions help us find the range algebraically?

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Inverse functions can be used to find the range of a function algebraically, as demonstrated with the function y = 125 - 12x. The inverse function is calculated as f^{-1}(x) = (125 - x)/12, indicating that the range of the original function corresponds to the domain of its inverse. It is noted that this method is applicable primarily to one-to-one functions, and for functions that are not one-to-one, the domain may need to be restricted to ensure a one-to-one relationship. The discussion highlights the importance of graphical analysis and calculus in understanding more complex functions. Overall, understanding inverse functions is crucial for determining ranges in algebraic contexts.
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Find the range algebraically.

y = 125 - 12x

There is a way to do this by finding the inverse function. Can someone show me how to apply the idea of inverse functions to find the range?
 
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$f(x)=125-12x$, a 1-1 function

inverse is $f^{-1}(x) = \dfrac{125-x}{12}$

the domain of $f^{-1}(x)$ is $\mathbb{R} \implies$ range of $f(x)$ is $\mathbb{R}$
 
This function is one-to-one. Can we find the inverse of functions that are not one-to-one?

You found the inverse of the given function.

You then said that the domain of the inverse is the range of the original function.

Correct?

Can this method be applied to all functions?
 
Finding the inverse of a function is not always easy.

Sometimes the domain of the function in question must be restricted to force a 1-1 situation.

This is the reason why graphical analysis is so important. More complex graphs require the concepts of calculus to analyze.
 
You said:

"Sometimes the domain of the function in question must be restricted to force a 1-1 situation."

I am not too clear in terms of restricting a function "to force a 1-1 situation."

What do you mean by this statement which is so common in textbooks?
 
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