How can radial probability densities be huge when they should be less than 1?

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SUMMARY

The discussion centers on the calculation of radial probability densities in quantum mechanics, specifically using the formula P(r) = |rR(r)|^2. The user reports obtaining values around 10^8 for radial probability densities at r = 5.24a_o, where a_o is the Bohr radius (5.291772E-11 m). The confusion arises from the misconception that probability densities must be less than 1; however, the integral of P(r) over a specified range must equal 1, which can result in large values for P(r) when considering small intervals of r.

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jaejoon89
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I have ~5.24a_o where a_o is the Bohr radius given by 5.291772E-11 m. This is my r value. But I am getting HUGE radial probability densities ~10^8! How is this possible? I thought they have to be less than 1 since it's a probability!

P(r) = |rR(r)|^2 = [r^2 / (8a_o^3)] [(2-r/a_o)^2] exp(-r/a_o)
 
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i think you're confusing probability denisty with probability

the probability of finding the electron in between r and r = dr is P(r).dr

So the integral of P(r).dr must be 1.

Although the limit of the integral goes from 0 to infinity, P(r) is only really non-zero for a few a_0. Thinking of the intergal in terms of area, as the span of r is so small, P(r) must be large for the integral to add up to one
 

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