How can the Rational Roots Theorem help with factoring?

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Homework Help Overview

The discussion revolves around the application of the Rational Roots Theorem in factoring polynomials, specifically in finding the highest common factor (HCF) of given polynomial expressions.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants explore the use of the Rational Roots Theorem to identify potential linear factors of polynomials. Questions arise regarding the process of finding the HCF and the reasoning behind stopping at certain expressions during polynomial division.

Discussion Status

Some participants have provided guidance on using the Rational Roots Theorem as a starting point for factoring. There is an ongoing exploration of different polynomial expressions and their relationships, with multiple interpretations of the HCF process being discussed.

Contextual Notes

Participants note issues with the clarity of attachments and the complexity of polynomial expressions, which may affect the discussion. There is also mention of specific polynomial forms and operations being used in the context of finding the HCF.

Miike012
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Homework Statement



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The document shows too small and too blurry, even after I change the screen magnification;actually, the magnification seems to have no effect, even no change at 200%. It appears to be something about polynomial or synthetic division.
 
I added another attachment... I made it bigger...
if you can't read it... the problem is...

What is the HCF of
x^4 + 3x^3 +12x -16 and x^3 -13x+12
 
I have another quick question if you don't mind answering?

The question is what is the HCF of 2x^3 + 4x^2 - 7x -14 and 6x^3 - 10x^2 -21x +35

If I multiply 3 by the first equation then subtract from the second equation I get...

6x^3 - 10x^2 -21x +35 - 6x^3 - 12x^2 + 21x +42 = -22x^2 + 77 = -11(2^2-7)

HCF = (2^2-7)
How do I know to stop at -22x^2 + 77? And why isn't -11 included into the HCF? Is it because there isn't a simple factor in the two originals therefore there will not be a simple factor in the HCF?
 
Mike012,
This may be too simple compared to how you want to factor, but I would try some sense from the Rational Roots Theorem. Initially this would check for linear factors, but it would still give enough results for degree 2 or degree 3; there may be either a degree 2 which itself might not be factorable into linears, or there may be a degree 2 which is composed of two linears.
 

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