How can you determine isoclines using slope fields?

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Isoclines can be determined from slope fields by identifying curves where the slope remains constant. In a system of ordinary differential equations (ODEs), the solution is a parametrized curve represented as {x(t), y(t)}, and the tangent vector's slope is derived using the chain rule. The relationship between the functions is expressed as m = g(x, y, t) / f(x, y, t), where m is the slope. Isoclines are significant as they represent points where the slope does not change, particularly at nullclines where m equals zero or infinity. Understanding this relationship helps in visualizing the behavior of solutions in the phase plane.
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I can find many websites that show a slope field, an answer, and the isoclines but for the life of me I cannot figure out the relationship between slope fields and isoclines!

I need a nudge in the right direction please!
 
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When you have a system of ode's, your solution will be a parametrized curve in the plane (space), i.e. \{x(t),y(t)\}. If you derivate such curve, you obtain a vector tangent to such curve given by T=\{\dot{x}(t),\dot{y}(t)\}, where the dot denotes derivations with respect to time. From your calc & geometry classes, you should remember that the slope of the tangent vector is given by (using the chain rule):

m=\frac{d y/dt}{dx/dt}=\frac{dy}{dx}.

And there you go. If you have a given system

\begin{array}{l} \dot{x}(t)=f(x,y,t) \\ \dot{y}(t)=g(x,y,t)\end{array}

then the isoclines will be the curves where the slope

m=\frac{g(x,y,t)}{f(x,y,t)}

remains constant. Of particular importance are the nullclines (m=0 and m=\infty). (why?)
 
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