When you have a system of ode's, your solution will be a parametrized curve in the plane (space), i.e. [itex]\{x(t),y(t)\}[/itex]. If you derivate such curve, you obtain a vector tangent to such curve given by [itex]T=\{\dot{x}(t),\dot{y}(t)\}[/itex], where the dot denotes derivations with respect to time. From your calc & geometry classes, you should remember that the slope of the tangent vector is given by (using the chain rule):
[tex]m=\frac{d y/dt}{dx/dt}=\frac{dy}{dx}[/tex].
And there you go. If you have a given system
[tex]\begin{array}{l} \dot{x}(t)=f(x,y,t) \\ \dot{y}(t)=g(x,y,t)\end{array}[/tex]
then the isoclines will be the curves where the slope
[tex]m=\frac{g(x,y,t)}{f(x,y,t)}[/tex]
remains constant. Of particular importance are the nullclines ([itex]m=0[/itex] and [itex]m=\infty[/itex]). (why?)