How Can You Determine Roots of a Quadratic in Any Field?

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SUMMARY

The discussion focuses on determining the roots of a quadratic polynomial f(x) = ax^2 + bx + c in any field F, specifically when (2a) is a unit in F. The quadratic formula is established based on the discriminant delta = b^2 - 4ac. It is concluded that if there exists a k in F such that k^2 = delta, then the roots are given by (-b ± k)/(2a). Conversely, if no such k exists, the polynomial has no roots in F. Additionally, the quadratic 3x^2 + 2x + 5 is analyzed for irreducibility in the fields (Z/pZ) for primes p = {7, 11, 13, 23}.

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Let F be a field. Suppose f(x)=ax^2+bx+c is an element of F[x] with (2a) a unit in F, and set delta=b^2-4ac. Prove the following version of the quadratic formula. Hint: for (a) and (b) use the identity 4a x f(x)=(2ax+b)^2-delta.

(a) If there is a k in F such that k^2=delta, then (-b plus or minus k)/(2a) are roots of f(x).

(b) If there is no k in F such that k^2=delta, then f(x) has no roots in F.

(c) Use the quadratic formula to factor 3x^2+2x+5 in (Z/pZ)[x] into irreducibles for primes p in {7,11,13,23}.

I have no idea how to do this one. I started with part (c), by factoring these things. Then I tried to figure out k for these, and it gave roots that were completely different than the ones I got when I factored, which has confused me more. Help please.
 
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Part (a) should be really easy. How can you tell whether f(x)=0 when x=(-b plus or minus k)/(2a)?
 

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