How Can You Rewrite an Equation to Express y as a Function of x?

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Discussion Overview

The discussion focuses on rewriting an equation to express y as a function of x, specifically involving logarithmic transformations and algebraic manipulation. The context includes mathematical reasoning and problem-solving related to logarithmic equations.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant presents the original equation and suggests a method to rewrite it using logarithmic properties, indicating that the final expression may be complex.
  • Another participant provides a specific expression for y in terms of x, suggesting a potential solution.
  • A third participant offers an alternative approach to rewriting the equation, emphasizing the use of logarithmic properties to simplify the expression further.
  • A later reply acknowledges the benefit of collaborative input in clarifying the problem and improving the solution process.

Areas of Agreement / Disagreement

Participants explore different methods to express y as a function of x, with no consensus on a single approach. Multiple competing views and methods remain present in the discussion.

Contextual Notes

Participants express uncertainty about the complexity of the final expression and the effectiveness of various logarithmic manipulations, indicating that the steps may depend on specific interpretations of logarithmic properties.

karush
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$\tiny{6.5.95 Kamehameha HS}$

Express y as a function of x. $\quad C>0$
$3\ln{y}=\dfrac{1}{2}\ln{(2x+1)}-\dfrac{1}{3}\ln{(x+4)}+\ln{C}$
rewirte as
$\ln{y^3}=\ln{(2x+1)^{(1/2)}}-\ln{(x+4)^{(1/3)}}+\ln{C}$
then e thru and isolate y
i think
looks like it will be ugly
 
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$y = \dfrac{C_2\sqrt[6]{2x+1}}{\sqrt[9]{x+4}}$
 
karush said:
$\tiny{6.5.95 Kamehameha HS}$

Express y as a function of x. $\quad C>0$
$3\ln{y}=\dfrac{1}{2}\ln{(2x+1)}-\dfrac{1}{3}\ln{(x+4)}+\ln{C}$
rewirte as
$\ln{y^3}=\ln{(2x+1)^{(1/2)}}-\ln{(x+4)^{(1/3)}}+\ln{C}$
I would have said, instead,
$ln(y)= \ln((2x+1)^{1/6})- \ln((x+4)^{1/9})+ ln(C)$
and then use the properties of the logarithm
$ln(y)= \ln\left(\frac{C(2x+1)^{1/6}}{(x+ 4)^{1/9}}\right)$

then e thru and isolate y
i think
looks like it will be ugly
Now, it doesn't look so ugly!
 
well that certainly helped a lot
pays to get more input
 

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