How change from one to another coordinate system

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Discussion Overview

The discussion revolves around converting coordinates from one system to another, specifically from (r, s) to (x, y) and then to (ζ, η). The focus is on deriving the Jacobian matrix necessary for integrating a function over a specified region.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant seeks assistance in converting coordinates and requires the Jacobian matrix for integration.
  • Another participant provides a general formula for the Jacobian matrix and suggests a specific parametrization for the new coordinates.
  • A question is raised about the relationship between the parameter t in the equation and the angle phi in the provided picture.
  • A clarification is given that the inverse equations should be used for the specific case of converting from (r, phi) to (x, y).

Areas of Agreement / Disagreement

Participants appear to agree on the need for a Jacobian matrix and the general approach to coordinate transformation, but there are nuances regarding the specific parametrization and the interpretation of variables that remain unaddressed.

Contextual Notes

The discussion does not resolve the specific assumptions regarding the coordinate systems or the integration function, and the dependency on the definitions of the variables is not fully explored.

soks
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Hello!

I have a problem. How can I convert a left part from picture which is in coordinate system
(r, s) to coordinate system (x, y) and then to coordinate system (ζ, η) (right part). I need Jacobian matrix because of integration some function above this region.

Any helpful links or answers are welcome.

http://img442.imageshack.us/img442/3074/20121122230303.jpg
 
Last edited by a moderator:
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Given a parametrization for your new coordinates (e.g. x=r cos(t), y=r sin(t), the new coordinates are:

[tex]\left(\begin{array}{cc}x'\\y'\end{array}\right)=det(Jacobian(x,y)) \left(\begin{array}{cc}x\\y\end{array}\right)[/tex]

Where the Jacobian is merely:

[tex]J=\left(\begin{array}{cc}\frac{\partial x}{\partial r}&\frac{\partial x}{\partial t}\\\frac{\partial y}{\partial r}&\frac{\partial y}{\partial t}\end{array}\right)[/tex]
 
Thanks for answer.

Is parameter t in equation x = r cos(t) angle phi in the picture?
 
Yes, but this was the general formula. In your case, you are going from r,phi to x,y so you should take the inverse equations, i.e.

[tex]r=\sqrt(x^2+y^2) , t=atan(y/x)[/tex]

You would then have r,t on the left hand side of the equation and the new Jacobian times x,y on the other one.
 
Ok. Thank you
 

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