How Close to Speaker B Must You Be for Destructive Interference at 172 Hz?

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SUMMARY

The discussion centers on calculating the distance from speaker B for destructive interference of sound waves at a frequency of 172 Hz. Given the speed of sound at 344 m/s, the wavelength is determined to be 2 meters. The closest distance to speaker B for destructive interference, while standing 8 meters from speaker A, is calculated to be 1 meter. The relationship between the distances from both speakers is expressed using the equation ΔL/λ = (n + 0.5), where n is an integer.

PREREQUISITES
  • Understanding of wave interference principles
  • Knowledge of sound wave frequency and wavelength calculations
  • Familiarity with basic algebra and equations
  • Concept of phase difference in sinusoidal waves
NEXT STEPS
  • Study the principles of wave interference in more detail
  • Learn about the applications of the wave equation in acoustics
  • Explore the concept of phase difference and its impact on sound waves
  • Investigate real-world examples of destructive interference in sound systems
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, acoustics, and sound engineering. This discussion is also beneficial for educators teaching concepts related to sound waves and interference patterns.

sreya
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Homework Statement



Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitted by each speaker is 172 Hz. You are 8.00 m from speaker A. Take the speed of sound in air to be 344 m/s.

What is the closest you can be to speaker B and be at a point of destructive interference?
Express your answer in meters.

Homework Equations



f = \frac{v}{\lambda}
\frac{\Delta L}{\lambda} = .5,1.5,2.5,...

The Attempt at a Solution



\lambda = 344/172 = 2

1/2 = .5 => Ans:1m

The odd thing is that it tells you the distance you are from A but wants to know how close you can get to B but you don't know the distance between the two.

The answer is 1, since that would give you 1/2 = .5 but that seems like to me that you're 1m away from A, since we don't know how close we are to B
 
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It might help to use more explicit notation for the various distances. Let ##d_A## be your distance from speaker A and ##d_B## your distance from speaker B. You are given ##d_A = 8##m, but let's keep using the symbol ##d_A##. We can plug in numbers later.

You wrote ##\frac{\Delta L}{\lambda} = .5, 1.5, 2.5, ...##.

You can write this as ##\frac{\Delta L}{\lambda} = (n+\frac{1}{2})## where ##n = 0, 1, 2, ...##.

Can you express this equation in terms of the symbols ##d_A## and ##d_B##?
 

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