- #1

- 30

- 7

I know he had this ratio:

But how did he get this:

?

But how did he get this:

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- Thread starter erocored
- Start date

- #1

- 30

- 7

I know he had this ratio:

But how did he get this:

?

But how did he get this:

- #2

- 30

- 7

- #3

Mark44

Mentor

- 35,052

- 6,791

The result uses a formula for the sum of squares.

$$\sum_{k=1}^m k^2 = \frac{m(m + 1)(2m + 1)}6$$

Replace ##1^2 + 2^2 + \dots + m^2## in your first equation by the above, and you will get the result shown in the second equation.

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