B How did Cavalieri get his formula for the area underneath a parabola?

erocored
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I know he had this ratio:
1604325468203.png

But how did he get this:
1604325593307.png
?
 
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1604325899893.png
 
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erocored said:
I know he had this ratio:
View attachment 272042
But how did he get this:
View attachment 272043 ?
The result uses a formula for the sum of squares.
$$\sum_{k=1}^m k^2 = \frac{m(m + 1)(2m + 1)}6$$
Replace ##1^2 + 2^2 + \dots + m^2## in your first equation by the above, and you will get the result shown in the second equation.
 
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