How Do Acids and Bases Interact in Reactions?

Click For Summary
SUMMARY

This discussion focuses on the interaction of acids and bases, specifically the reactions involving nitric acid (HNO3) and potassium hydroxide (KOH) when added to water. The participant correctly identifies that HNO3 donates a proton to water, forming hydronium (H3O+) and nitrate (NO3-). However, confusion arises regarding the reaction of KOH in water and the subsequent reaction between HNO3 and KOH, which ultimately produces water and potassium nitrate (KNO3). The participant seeks clarification on the proton donation process and the dissociation of KOH as an Arrhenius base.

PREREQUISITES
  • Understanding of acid-base reactions and proton transfer
  • Familiarity with Arrhenius definitions of acids and bases
  • Knowledge of chemical equations and reaction products
  • Basic concepts of ion formation in aqueous solutions
NEXT STEPS
  • Study the dissociation of KOH in water and its role as an Arrhenius base
  • Learn about the Bronsted-Lowry theory of acids and bases
  • Explore the concept of neutralization reactions and their products
  • Investigate the role of hydronium ions in acid-base chemistry
USEFUL FOR

Chemistry students, educators, and anyone seeking to deepen their understanding of acid-base interactions and reaction mechanisms.

baylin
Messages
2
Reaction score
0
Sorry guys,

I can't seem to grasp the concept:

It deals with acids and bases. When the acid donates the proton, to the base, how do we know how many is transferred and how many the base can accept? This is where I am stumped.


Homework Statement



What ions are formed when nitric acid, HNO3 is added to water?

The Attempt at a Solution



HNO3 + H2O -----> H3O + NO3

My Thought Process: The HNO3 is the acid, and since it donates the proton, we give off one proton, the H, to the other reactant, H2O.


The next part says:

Homework Statement



What ions are formed when potassium hydroxide is added to water?

The Attempt at a Solution



KOH + H2O -------> KOH2 + HO

My Thought Process: The H2O is the acid and it donates one proton to the other reactant, the H, to the other reactant KOH.


The next part says:

Homework Statement



If these two solutions are poured together, what is the reaction that would occur?

The Attempt at a Solution



I am not sure here. Are they talking about the "two solutions" meaning the nitric acid and the potassium hydroxide? If they are:

HNO3 + KOH ------> KOH2 + NO3

My Thought Process: The nitric acid is the acid here, so it gives off one proton, the H, to the other reactant, KOH.


I think I have the first one right, but I doubt I have the second one. I am sure if someone can please explain the thought process of what goes on in your head, I can understand it and deduce it from there. Is it always just ONE H that is donated? I tried reading the book, most of the time I understand it, as the book ("Introduction to CHEMISTRY" by Tro) it great! But this time I don't understand this section at all.

Thanks for any input!
 
Physics news on Phys.org
baylin said:
KOH + H2O -------> KOH2 + HO

Nope. KOH is an Arrhenius base. Google/check what it means and how it dissociates.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K