How Do Boundary Conditions Affect Wave Functions in a Particle in a Box Problem?

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Homework Help Overview

The discussion centers around the particle in a box problem, specifically focusing on how boundary conditions influence the wave functions derived from the time-independent Schrödinger equation for a particle in an infinitely deep square well.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the derivation of wave functions and the implications of boundary conditions on the solutions, including the roles of sine and cosine functions. Questions arise regarding the necessity of both types of solutions and the normalization process.

Discussion Status

The conversation is ongoing, with some participants offering insights into the nature of the solutions and boundary conditions. There is an exploration of different interpretations regarding the use of sine and cosine functions, and the discussion reflects a productive exchange of ideas without reaching a consensus.

Contextual Notes

Participants are navigating the implications of specific boundary conditions, such as Psi(-L/2) = 0 and Psi(L/2) = 0, and how these affect the wave functions and their normalization.

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Homework Statement



Assume we have an infinitely deep square well of length L, with the left edge of the well at -L/2. Assume U = 0 at the bottom and infinity at the top. A) Using the time independent Schrödinger Equation, derive the wave equation for a particle trapped in this well. Make sure your equation is properly normalized

Homework Equations


shrodingers equation, the general solution to it which is Asinkx +Bcoskx=psi(0)


The Attempt at a Solution


I know that sin is and odd function and cos is even so I am supposed to arrive at two wave functions and have different values of n, even values for cos and odd for sin. I am supposed to get Psi(x)= (2/L)^.5sin(npix/L) where n is odd values and the same thing except cos and even values. I am having trouble deriving this using my boundary conditions, and I am also having trouble normalizing it.
 
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I would save normalization for the end. What are your boundary conditions so far?
 
Why is it that you can get sine and cosine solutions? i thought all you needed was the sine solution because it would always satify the boundary conditions of haveing a node at each boundary.
 
Well both satisfy Schrodingers equations. If the boundary conditions were Psi(0) = 0 and Psi(L) = 0, then sine would be your only solution because cos(0) = 1. But now your BC's are Psi(-L/2) = 0 and Psi(L/2) = 0. Therefore both can be solutions. You just need to find the 'k' that satisfies those BC's.
 

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