How Do Bragg Peak Intensity Ratios Differ in Ca and CaF2 X-Ray Diffraction?

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The discussion focuses on the differences in Bragg peak intensity ratios between Calcium (Ca) and Calcium Fluoride (CaF2) in X-ray diffraction patterns. It establishes that the (4 0 0) planes in CaF2 intersect both Calcium and Fluorine ions, while the (2 0 0) planes only intersect Calcium ions. Despite this, the computed intensity ratios for the (2 0 0) and (4 0 0) peaks appear identical due to the cancellation of the additional structure factor from Fluorine in CaF2. Participants emphasize the importance of accurately accounting for all atoms in the structure factor formula.

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Question statement: We are given that Ca and CaF2 are both Ca face-centred cubic lattices, and that in the case of CaF2 there is a basis of F ions at +/-(1/4, 1/4, 1/4). Then explain qualitatively how the ratio of the (2 0 0) and (4 0 0) Bragg peak intensities in the X-ray diffraction patterns of Ca and CaF2 would differ.

Attempt at Solution: The main difference I can think of is that the planes defined by (4 0 0) would go through the F ions as well as Ca ions in the CaF2 lattice whereas the (2 0 0) planes would not intersect any F ions. In contrast the (4 0 0) planes and (2 0 0) planes in Ca would intersect the same atoms, and there would be empty planes in the (4 0 0) case.

However when I try to compute the ratios I get that they are the same, as the extra structure factor in the case of CaF2 just cancels itself out when comparing the (4 0 0) and (2 0 0) structure factors.

Any input would be appreciated.
 
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Are you sure you put all the terms in the structure factor formula? How many fluorine atoms have you considered in the conventional cell?
 

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