How Do Fermion and Scalar Fields Interact in Lorentz Invariant Terms?

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SUMMARY

The discussion centers on the interaction terms between fermion fields (\(\psi\)) and scalar fields (\(\phi\)) in Lorentz invariant terms. A common interaction form is \(\psi^{\dagger}A\psi\phi\), where \(A\) is a Lorentz invariant matrix such as \(\gamma^{5}\). The inclusion of derivative terms, such as \(\partial_{\mu}\psi^{\dagger}A\partial^{\mu}\psi\phi\), is debated, with the conclusion that these terms often lead to nonrenormalizable theories unless their coupling constants are small. The dimensional analysis of these coefficients indicates that they become significant only at high energy scales, making them negligible in low-energy experiments.

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  • Understanding of Lorentz invariance in quantum field theory
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neworder1
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What is the most general reasonable form of the Lorentz invariant interaction term between a fermion field \psi and a scalar field \phi?

A common choice for the interaction is something like \psi^{\dagger}A\psi\phi, with A being a Lorentz invariant matrix (like \gamma^{5}). However, I don't see why an interaction couldn't include terms with arbitrary number of derivatives of fields, as long as it's Lorentz invariant (e.g. \partial_{\mu}\psi^{\dagger}A\partial^{\mu}\psi\phi or \psi^{\dagger}A\partial_{\mu}\psi\partial^{\mu}\phi).

Is there any physical reason for discarding such interaction terms with derivative coupling, or maybe we simply don't need them to describe real world interactions?
 
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Yes, there is a reason. Their coefficients have dimensions of (mass)^{-n} (with n \geq 1). We usually work with effective theories, which are presumed to reduce to some more accurate theory at some very high energy scale. When a coupling constant has units of some power of mass, that mass will typically be around the energy scale at which the more accurate theory becomes important. So for experiments at energy scales much smaller than that scale, these couplings can be considered to be very small. Also, when a coupling has dimensions of inverse mass, it usually causes the theory to be nonrenormalizable. This is not a problem if the coupling is very small, because by the time you move the cutoff to a scale where it becomes a problem, the more accurate theory takes over. But if the coupling constant is large (compared to the scale you're working at), it usually is a problem.
 

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