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Oh I supposed the points of contacts to be links. Thanksbrainpushups said:It means find the force between links that are next to each other. So what is the force between the 1st and 2nd link, the 2nd and 3rd link, etc.
The forces between 1st and 2nd would be (0.4)(9.8+2.5) applied by 2nd and the same by 1st. Am I right?shayan haider said:Oh I supposed the points of contacts to be links. Thanks
Is the force on 1st link = (0.5)(9.8+2.5)shayan haider said:The forces between 1st and 2nd would be (0.4)(9.8+2.5) applied by 2nd and the same by 1st. Am I right?
OkSteamKing said:According to the problem sketch, the mass of each link in the chain is 100 g.
Use this fact and draw a free body diagram of the forces acting on each link due to the applied acceleration.