How Do Forces Affect Motion in Different Scenarios?

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SUMMARY

This discussion focuses on the application of Newton's laws of motion in various scenarios involving forces and accelerations. Key examples include an airplane's takeoff with an 8000N upward force at a 65-degree angle, the tension in ropes supporting blocks in an upward-accelerating elevator, and the weight readings on a spring scale during an elevator's motion. Participants provide calculations for weight, tension, and forces, demonstrating the principles of dynamics and kinematics in real-world contexts.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of forces and acceleration calculations
  • Familiarity with gravitational force equations (Fg = mg)
  • Concept of tension in ropes and its relation to acceleration
NEXT STEPS
  • Study the concept of vector decomposition of forces in physics
  • Learn about the dynamics of elevators and the forces acting on objects within them
  • Explore the principles of uniform acceleration and deceleration in motion
  • Investigate the effects of varying forces on objects in different scenarios
USEFUL FOR

Students studying physics, educators teaching dynamics, and anyone interested in understanding the practical applications of forces and motion in everyday scenarios.

willingtolearn
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#1
On takeoff, the combined action of the engines and wings of an airplane exerts an 8000N force on the plane, directed upward at an angle of 65* above the horizontal. The plane rises with constant velocity in the vertical direction while continuing to accelerate in the horizontal direction.
a) What is the weight of the plane ?
b) What is its horizontal acceleration ?
-------------------------------
V (initial)= 0
weight = mass time gravity
weight = 9.8 time mass
acceleration in vertical direction = 0 (constant speed)
F (apply) = 8000 N
From F = ma --> m = F / a
And I stuck at this point !


#2
Two blocks are fastened to the ceiling of an elevator. Each block is 10 kg. The elevator accelerates upward at 2 m/s2 (at the block that close to the ceiling). Find the tension in each rope.
------------------------------

F (upper) = 100 N
F (lower) = 100 * 2 = 200 N


#3
A 72 kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in .80s. It travels with this constant speed form 5 s, undergoes a uniform negative acceleration for 1.5 s and comes to rest. What does the spring scale registered (a) before the elevator starts to move ? (b) during the first .8 s ? (c) while the elevator is traveling at constant speed ? (d) during the negative acceleration ?
--------------------------------
a) Weight = 72*9.8 = 705.6 N because Fg = m*g
b) From V (intial) = 0 V (final) = 1.2 m/s t = .8 s
so a = 1.5 m/s2.
F = 705.6 + F (that is accelerating) ==> 705.6 + 72 (1.5) = 813.6 N
c) 705.6 N
d) I don't get what is this say "undergoes a uniform negative acceleration for 1.5 s and comes to rest"

Help Please ? Thanks
 
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willingtolearn said:
#1
On takeoff, the combined action of the engines and wings of an airplane exerts an 8000N force on the plane, directed upward at an angle of 65* above the horizontal. The plane rises with constant velocity in the vertical direction while continuing to accelerate in the horizontal direction.
a) What is the weight of the plane ?
b) What is its horizontal acceleration ?
-------------------------------
V (initial)= 0
weight = mass time gravity
weight = 9.8 time mass
acceleration in vertical direction = 0 (constant speed)
F (apply) = 8000 N
From F = ma --> m = F / a
And I stuck at this point !
Hints;
  1. How much force is airplane exerting vertically
  2. How much force is it exerting horizontally
willingtolearn said:
#2
Two blocks are fastened to the ceiling of an elevator. Each block is 10 kg. The elevator accelerates upward at 2 m/s2 (at the block that close to the ceiling). Find the tension in each rope.
------------------------------

F (upper) = 100 N
F (lower) = 100 * 2 = 200 N
I'm not sure how you've calculated 100N, but it's wrong.
willingtolearn said:
#3
A 72 kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in .80s. It travels with this constant speed form 5 s, undergoes a uniform negative acceleration for 1.5 s and comes to rest. What does the spring scale registered (a) before the elevator starts to move ? (b) during the first .8 s ? (c) while the elevator is traveling at constant speed ? (d) during the negative acceleration ?
--------------------------------
a) Weight = 72*9.8 = 705.6 N because Fg = m*g
b) From V (intial) = 0 V (final) = 1.2 m/s t = .8 s
so a = 1.5 m/s2.
F = 705.6 + F (that is accelerating) ==> 705.6 + 72 (1.5) = 813.6 N
c) 705.6 N
d) I don't get what is this say "undergoes a uniform negative acceleration for 1.5 s and comes to rest"
Answers (a) through (c) are correct. (d) simply means decceleration.
 
Can you give me some hints for problem 2 please ?
 
Sorry to bring up an old dead topic but I just got problem 3 for homework. What I did for d:
Find acceleration: a=(0Vf-1.2Vo(top speed of elevator ascending))/1.5time stated = -.8.
Net force = 705.6Normal weight+((72mass)x(-.8acceleration)) = 648N

Any mistakes?
 

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