How Do I Adjust a Formula to Alternate Sequence Terms?

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whatlifeforme
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Homework Statement


I am trying to solve this problem and need help with one aspect.

Homework Equations


sequence: 0,-1,0,1 -- repeated.

The Attempt at a Solution


How do I make every 4th term of the sequence a negative number?

for instance i have: (1 + (-1)^n)/2 but i don't know how to alternative the -1 term in.
 
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whatlifeforme said:

Homework Statement


I am trying to solve this problem and need help with one aspect.

Homework Equations


sequence: 0,-1,0,1 -- repeated.

The Attempt at a Solution


How do I make every 4th term of the sequence a negative number?

for instance i have: (1 + (-1)^n)/2 but i don't know how to alternative the -1 term in.
What functions are you willing to use.

This can easily be done with sine or cosine .

You can probably come up with some solution using the "mod" function.
 
please explain how i would implement cosine or sine.
 
Try sin (n*pi/2) and add integer constants to n to shift the series.
 
then you are going 1, 0, -1, 0. (so if i put sin(pi/2 + npi/2) into the ratio, then i multiply by negative 1 the correct number of times, but what about the zeros? sinx=0 ---> v(sinx) = 0
 
whatlifeforme said:
then you are going 1, 0, -1, 0. (so if i put sin(pi/2 + npi/2) into the ratio, then i multiply by negative 1 the correct number of times, but what about the zeros? sinx=0 ---> v(sinx) = 0
So, it appears you're starting with n = 1 .

Why is it that you say that [itex]\displaystyle \ -\,\sin\left(\frac{\pi}{2}+\frac{n\pi}{2}\right)\[/itex] doesn't work ?