How do I calculate electricity usage in units?

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To calculate electricity usage, multiply the power rating of the appliance in kilowatts (kW) by the time it is used in hours. For example, a 2.5 kW appliance used for 8 hours consumes 20 kWh (2.5 kW * 8 hours). Electricity is measured in kilowatt-hours (kWh), which represents the energy consumed over time. This measurement simplifies understanding energy usage compared to using joules directly. The discussion clarifies the relationship between power, time, and energy consumption, making it easier for beginners to grasp.
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How can I work out how many units of electricty are consumed in problems such as the following?

During one day, a 2.5 kW appliance was used for 8 hours. How many Units of electricity were used?

I know that the answer is 20 but I have no idea how that figure is arrived at. Also, in what unit is the electricity measured. What exactly does "20 units of electricy" mean?

Thanks a lot
 
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kW is a measure of power = the rate of energy used (kW = 1000J/s)
Electricity is sold in units of kWh = one kilowatt for one hour ( = 1000J/s * 3600s = 3,600,000J )
So a 2.5 kW appliance used for 8 hours = 2.5kW * 8h = 20kWh
 
Thanks a lot for your help.
So a 2.5 kW appliance means an appliance that consumes 2.5kW of energy if it runs for 1hour, is that right? Sorry, I'm a real beginner!
 
Gringo123 said:
So a 2.5 kW appliance means an appliance that consumes 2.5kW of energy if it runs for 1hour, is that right?
Not quite, 2.5kW is a unit of power, it is using 2.5 kJ (2500J) of energy per second.
So after one hour it has used = 2500 J/s * 3600s = 9MJ = 2.5kWh of electricity.

It's a bit strange using power (which is energy/time) multiplied by time to get back to energy - but Joules gives large numbers and kW and hours are more convenient for everday use it's easier.

It's a bit like if we measured distance by having a unit of car speed (mph) and instead of saying it was 30miles to town we said it was 30mph-hours. So after one hour at 30mph you have gone 30 miles.
 
mgb_phys said:
Not quite, 2.5kW is a unit of power, it is using 2.5 kJ (2500J) of energy per second.
So after one hour it has used = 2500 J/s * 3600s = 9MJ = 2.5kWh of electricity.

It's a bit strange using power (which is energy/time) multiplied by time to get back to energy - but Joules gives large numbers and kW and hours are more convenient for everday use it's easier.

It's a bit like if we measured distance by having a unit of car speed (mph) and instead of saying it was 30miles to town we said it was 30mph-hours. So after one hour at 30mph you have gone 30 miles.

Thanks a lot for that! It's a lot clearer now.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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