Apr 16, 2005 #1 apchemstudent Messages 220 Reaction score 0 How would you go about to solve this quesiton? I thought that to calculate this i had to set up an equation as: let x = the percentage of 85-Rb 84.91*x + 86.91*(1-x) = 85 x = 96%, but that's obviously wrong. How do i solve this question? Attachments atomic mass question 2.jpg 8.7 KB · Views: 508
How would you go about to solve this quesiton? I thought that to calculate this i had to set up an equation as: let x = the percentage of 85-Rb 84.91*x + 86.91*(1-x) = 85 x = 96%, but that's obviously wrong. How do i solve this question?
Apr 16, 2005 #2 GCT Science Advisor Homework Helper Messages 1,745 Reaction score 0 This may work \frac{84.91x+86.91y}{x+y}=85 solve for x/y, or the x in terms of y find (100)x/(x+y)
Apr 16, 2005 #3 apchemstudent Messages 220 Reaction score 0 GCT said: This may work \frac{84.91x+86.91y}{x+y}=85 solve for x/y, or the x in terms of y find (100)x/(x+y) nevermind... i know how to solve it now. It's referring to the actual weight of Rb - 85.
GCT said: This may work \frac{84.91x+86.91y}{x+y}=85 solve for x/y, or the x in terms of y find (100)x/(x+y) nevermind... i know how to solve it now. It's referring to the actual weight of Rb - 85.
Apr 16, 2005 #4 GCT Science Advisor Homework Helper Messages 1,745 Reaction score 0 85.4678 is the actual weight, average weight. http://www.webelements.com/webelements/elements/text/Rb/key.html \frac{84.91x+86.91y}{x+y}=85.4678
85.4678 is the actual weight, average weight. http://www.webelements.com/webelements/elements/text/Rb/key.html \frac{84.91x+86.91y}{x+y}=85.4678