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How do i factor this36(2x-y)^2-25(u-2y)^2

  1. Feb 6, 2007 #1
    how do i factor this
    36(2x-y)^2-25(u-2y)^2

    i was thinking to expand the brackets first?? but im not really sure
     
  2. jcsd
  3. Feb 6, 2007 #2

    mathman

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    In general the difference of two squares (which is what you have) is easily factored.

    a^2-b^2=(a+b)(a-b)
     
  4. Feb 6, 2007 #3
    alright so once i've got that what do i do with the 25 and 36 outside the brackets
     
  5. Feb 6, 2007 #4

    matt grime

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    Once you 'do that' you don't have any 25 or 36 outside any brackets.
     
  6. Feb 6, 2007 #5
    5^2 = 25
    6^2 = 36
     
  7. Feb 7, 2007 #6

    Gib Z

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    Let 2x-y=A and u=2y=B

    36(A^2) - 25(B^2)= (6A)^2 - (5B)^2
     
  8. Feb 7, 2007 #7
    Since we know 6^2 = 36 could you do it easier if it was written as: 36(2x-y)^2 = 6^2(2x-y)^2 = [(6)(2x-y)]^2 and you did the same process to simplify the other term.
     
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