- #1

karush

Gold Member

MHB

- 3,269

- 5

$\tiny{166.2.6.5}$

Find y'

$$x^2-4xy+y^2=4$$

dy/dx

$$2x-4(y+xy')+2yy'=2x-4y-4xy'+2yy'=0$$

factor

$$y'(-4x+2y)=-2x+4y=$$

isolate

$$y'=\dfrac{-2x+4y}{-4x+2y}

=\dfrac{-x+2y}{-2x+y}$$

typo maybe not sure if sure if factoring out 4 helped

Find y'

$$x^2-4xy+y^2=4$$

dy/dx

$$2x-4(y+xy')+2yy'=2x-4y-4xy'+2yy'=0$$

factor

$$y'(-4x+2y)=-2x+4y=$$

isolate

$$y'=\dfrac{-2x+4y}{-4x+2y}

=\dfrac{-x+2y}{-2x+y}$$

typo maybe not sure if sure if factoring out 4 helped

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