How do I find the equation of this parabola?? I am given a parabola with a "way line" l: x+y+2 = 0 and focus point F = (1;1). How do I find it's equation? I know I am suppost to shift it in some way and maybe mirror it, not sure how though. Need some help. The equation of a parabole is y^2 = px, whereas x=-P/4 is the way line and F = (p/4;0) is the focus point. I assume I am suppost to start with a parabole with focus point F = (1;0), p = 4 and way line l: x=-1. Now I tried shifting it around (0;1) to get F = (1;1), p = 4 and way line l: x=-2. I am almost there, but now I lack the Y, where on earth does that Y come from? where do I go from there? EDIT: I think going the opposite way is better but I still stop at the same spot: I get l: x = -y -2 & F = (1;1). 1: shift around (0;-1) get: x= -(y-1) - 2 = -y -1 & F = (1;0) I am now closing in but all I need to do is get rid of the "-y". No idea how to do that. EDIT: Nevermind. I have found the solution, using the definition of a parabole lPFl = dist(p,l). Case dismissed.