How do I parameterize these surfaces?

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Homework Help Overview

The discussion revolves around the parameterization of two surfaces, ##S_1## and ##S_2##, where ##S_1## is defined by the equation ##x^2+y^2=4## and is bounded above by the plane ##2y+z=6## and below by the ##xy## plane. ##S_2## represents the bottom disk of the surface.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the parameterization of the surfaces, with one suggesting a potential expression for ##S_1## and questioning the z boundaries related to the parameterization. Others express uncertainty about how to combine the parameterizations into a single expression and note that the proposed z boundary does not constitute a full parameterization. There is also a mention of preparing for a surface integral and questions about the appropriate normal vector to use.

Discussion Status

The discussion is ongoing, with participants exploring various approaches to parameterization and raising questions about the clarity of the problem statement and the specifics of the integral setup. There is no explicit consensus yet, but several lines of reasoning are being examined.

Contextual Notes

There is uncertainty regarding the completeness of the problem statement, as one participant questions whether all necessary information has been provided. Additionally, there are discussions about the conventions for normal vectors in the context of surface integrals.

Sho Kano
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Homework Statement


Parameterize ##S={ S }_{ 1 }\bigcup { { S }_{ 2 } } ##, where ##S_1## is the surface with equation ##x^2+y^2=4## bounded above by the graph of ##2y+z=6## and below by the ##xy## plane. ##S_2## is the bottom disk

Homework Equations

The Attempt at a Solution


##{ S }_{ 1 }=\left< 2cosu,2sinu,v \right> ,0\le u\le 2\pi ,0\le v\le 6-2y\\ { S }_{ 2 }=\left< rcosu,rsinu,0 \right> ,0\le u\le 2\pi ,0\le r\le 2##It doesn't make sense with the z boundaries because ##6-2y## isn't in terms of ##u## and ##v##...would it be ##6-4sinu##?
 
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I think that's the idea. I wouldn't know how to parametrize this in one single expression, ecxept also with a ##\cup## symbol (for the disc I would then use different parameter names).

Note: The ##\ 0\le v \le 6-4\sin u \ ## isn't a parametrization yet (imho).

##\LaTeX## note: use \sin and \cos, etc. Much clearer
 
BvU said:
I think that's the idea. I wouldn't know how to parametrize this in one single expression, ecxept also with a ##\cup## symbol (for the disc I would then use different parameter names).

Note: The ##\ 0\le v \le 6-4\sin u \ ## isn't a parametrization yet (imho).

##\LaTeX## note: use \sin and \cos, etc. Much clearer
this is OK in preparation for a surface integral right? Next I'd compose ##F## (the vector field) with ##S_1## and ##S_2## with two integrals, then dot that with the normal from each parameterization. But it's not clear which normal would I use? Inner or outer? is outer the conventional choice?
 
What integral ? Have we seen the full problem statement yet ?
 

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