How do I plot a distance-time graph using TikZ?

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Discussion Overview

The discussion revolves around plotting a distance-time graph using TikZ, specifically addressing the calculation of average speeds over specified time intervals and verifying the correctness of the graph based on these calculations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant seeks help in plotting a distance-time graph and verifying that the speed in the final 6 seconds is twice that of the first 6 seconds.
  • Another participant provides the formula for average speed and calculates the average speeds for both time intervals, suggesting a method to demonstrate the relationship between them.
  • A later post confirms the calculations of average speeds, stating that the speed in the first 6 seconds is indeed half of that in the last 6 seconds.
  • Multiple participants express approval of the plotted graph using TikZ, indicating that it appears correct.

Areas of Agreement / Disagreement

Participants generally agree that the calculations for average speeds are correct and that the plots look good, but there is no explicit consensus on the overall correctness of the graph as it relates to the initial request for help.

Contextual Notes

The discussion includes assumptions about the initial position and the interpretation of the plotted data, which may not be fully articulated or agreed upon by all participants.

mathlearn
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Problem

View attachment 6052

Plot the above given information in a Distance time graph.

View attachment 6051

View attachment 6050

Where do I need help

Hoping my graph is correct

Show that the speed in the final 6 seconds is twice the speed in first 6 seconds

But I'm having trouble here , I know $ distance=\frac{distance}{time} $

Many Thanks :)
 

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The average speed $\overline{v}$ over some time interval $\Delta t$ is given by the change in distance $d$ divided by the change in time.

So for the first 6 seconds (assuming the initial position is at 0), we have:

$$\overline{v}_1=\frac{\Delta d}{\Delta t}=\frac{30-0}{6-0}$$

And for the last 6 seconds, we have:

$$\overline{v}_2=\frac{\Delta d}{\Delta t}=\frac{90-30}{12-6}$$

Can you now show that $\overline{v}_2=2\overline{v}_1$?
 
MarkFL said:
The average speed $\overline{v}$ over some time interval $\Delta t$ is given by the change in distance $d$ divided by the change in time.

So for the first 6 seconds (assuming the initial position is at 0), we have:

$$\overline{v}_1=\frac{\Delta d}{\Delta t}=\frac{30-0}{6-0}$$

And for the last 6 seconds, we have:

$$\overline{v}_2=\frac{\Delta d}{\Delta t}=\frac{90-30}{12-6}$$

Can you now show that $\overline{v}_2=2\overline{v}_1$?

Thank you very much :)

First 6 seconds

$$\overline{v}_1=\frac{\Delta d}{\Delta t}=\frac{30-0}{6-0}$$

$$\overline{v}_1=\frac{30-0}{6-0}=\frac{30}{6}$$=5 meters per second

Last 6 seconds

$$\overline{v}_2=\frac{90-30}{12-6}=\frac{60}{6}=$$10 meters per second

Yes Now it is shown that first 6 second speed=2*last 6 second speed

Have I plot the distance time graph correctly? :)

Many Thanks :)
 
Yes, your plots look good to me. (Star)

Using our new TikZ feature:

\begin{tikzpicture}
%preamble \usepackage{pgfplots}
\begin{axis}
\addplot coordinates {(0,0) (2,10) (4,20) (6,30) (8,50) (10,70) (12,90)};
\end{axis}
\end{tikzpicture}
 
MarkFL said:
Yes, your plots look good to me. (Star)

Using our new TikZ feature:

\begin{tikzpicture}
%preamble \usepackage{pgfplots}
\begin{axis}
\addplot coordinates {(0,0) (2,10) (4,20) (6,30) (8,50) (10,70) (12,90)};
\end{axis}
\end{tikzpicture}

Thank you very much MarkFL ! (Happy) (Smile) (Party) , And that's when TIKz comes handy! :)
 

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