How Do I Rearrange Doppler Effect Equations to Solve for Specific Variables?

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The discussion focuses on rearranging Doppler Effect equations to isolate specific variables such as V, Vs, Vo, Fo, and Fs. The equations provided relate the observed frequency to the source frequency and the speeds of the observer and source. Key advice includes separating equations when dealing with the plus-or-minus sign and applying algebraic principles to isolate variables. Examples illustrate how to manipulate the equations effectively, emphasizing practice to gain confidence. Understanding these rearrangements is crucial for solving Doppler Effect problems accurately.
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I know which equations to use for solving Doppler Effect problems, so figuring out which is the observer and which is the source and which is moving or stationary is not the problem, the problem I am having is in solving the actual formulas... This question might belong in the math help section but I thought it was best to post this in the physics area because it does deal with a physics topic.

Anyway, I attached the equations as graphics (maybe somebody knows how to LATEX these?). I am looking for some help in rearranging these equations to solve for each of the variables, V,Vs,Vo,Fo,Fs.

Can somebody please help?

Thanks!
 

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  • Doppler EQ - Moving Observer.gif
    Doppler EQ - Moving Observer.gif
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  • Doppler EQ - Moving Source.gif
    Doppler EQ - Moving Source.gif
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f_{o}=f_{s}\left({1\pm \frac{V_{o}}{V}}\right)

f_{o}=f_{s}\left({\frac{1}{1\pm \frac{V_{s}}{V}}}\right)

As I understand it, you are having trouble manipulating the equations to isolate certain variables. I suspect it is the plus-or-minus that is giving you trouble. Let's do an example. Let's isolate V in the first equation.

f_{o}=f_{s}\pm \frac{f_{s}V_{o}}{V}}
Vf_{o}=Vf_{s}\pm f_{s}V_{o}
Vf_{o}-Vf_{s}=\pm f_{s}V_{o}
V(f_{o}-f_{s})=\pm f_{s}V_{o}
V=\pm \frac{f_{s}V_{o}}{f_{o}-f_{s}}

Hope that helps. Keep in mind that if you encounter problems handling a \pm sign, just separate the equation into the plus and minus forms, isolate the variable you wish in each equation normally, then unite the two final equations into one with a \pm. Think about what the symbol represents when dealing with it in your work.
 


Sure, I'd be happy to help. The equations for solving Doppler Effect problems can be a bit daunting at first, but with some practice and understanding, you'll be able to rearrange them to solve for any variable you need.

First, let's go over the equations. The first equation is for the frequency of the observed wave (Fo), which is equal to the frequency of the source wave (Fs) multiplied by the ratio of the speed of the wave (V) plus the speed of the observer (Vo) over the speed of the wave minus the speed of the source (Vs). This equation is used when the source or observer is moving.

The second equation is for the frequency of the source wave (Fs), which is equal to the frequency of the observed wave (Fo) multiplied by the ratio of the speed of the wave (V) minus the speed of the source (Vs) over the speed of the wave minus the speed of the observer (Vo). This equation is used when the source or observer is stationary.

To rearrange these equations, you will need to use algebraic principles such as isolating the variable you want to solve for and using inverse operations (e.g. if a variable is multiplied, divide to isolate it). It may also be helpful to plug in known values and solve for the unknown variable to get a better understanding of how the equations work.

For example, if you want to solve for the speed of the wave (V), you can rearrange the first equation to be V = (Fo - Fs) * (Vo + Vs) / (Fo + Fs). This would give you the speed of the wave in terms of the frequencies and speeds of the source and observer.

If you're still having trouble, don't hesitate to ask for more specific help or clarification. It's also a good idea to practice using these equations with different scenarios and values to get more comfortable with them. Good luck!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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