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I am to find the reactions at A. How would I set up the equations for A_{y} and A_{x} in this problem? It seems pretty confusing. Also, will there be a momentum in this problem?
You are using the wrong terminology;it's the moments (or torques) of all forces about A that must equal 0.Well for forces in the X direction, it's just A (in the X direction) is 0, right?
For y direction, this is the equation I wrote down.
A_{y} + 300 - 100 - 200 = 0
Solving for the unknown, I got A_{y} = 0.
As for the momentum of A, here's what I wrote down. It doesn't exactly make sense to me.
Since the support at A is fixed, it is capable of providing both forces and moment (or torque, or couple; these terms are sometimes used synonymously). So in your equation, you are missing the moment provided by the support at A.-100(12) + 300(15) - 200(22) = 0
but...that comes out to -1100 = 0 which makes no sense? What's going on? Is the momentum of A just -1100?
So the moment at A would be written like this?You are using the wrong terminology;it's the moments (or torques) of all forces about A that must equal 0.Since the support at A is fixed, it is capable of providing both forces and moment (or torque, or couple; these terms are sometimes used synonymously). So in your equation, you are missing the moment provided by the support at A.