How do I solve a quadratic inequality using factoring?

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    Inequality Quadratic
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Discussion Overview

The discussion revolves around solving the quadratic inequality x^2 + 4x - 32 < 0 using factoring. Participants explore methods for determining the intervals where the inequality holds true, including the use of number line analysis and sign evaluation of the factors.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents the inequality and factors it as (x - 4)(x + 8) < 0, identifying the roots x = 4 and x = -8.
  • Another participant suggests evaluating the signs of each factor to determine the sign of the quadratic in various intervals, noting that the roots are of odd multiplicity, which implies the sign will alternate across intervals.
  • A later reply indicates that the expression is negative across all three intervals but later corrects this to state that the signs actually alternate across the intervals.
  • Participants discuss picking test values from each interval to evaluate the original inequality, with one participant stating the results of these evaluations.
  • One participant confirms the expectation that the parabola opens upwards and is negative between its roots.

Areas of Agreement / Disagreement

There is some agreement on the method of evaluating the intervals and the behavior of the quadratic, but there is also confusion regarding the determination of the sign across the intervals, leading to corrections and clarifications. The discussion remains somewhat unresolved regarding the final solution.

Contextual Notes

Participants express uncertainty about whether to evaluate the chosen numbers in the original inequality or the factored form. There are also mentions of potential typos and corrections that may affect the clarity of the discussion.

Who May Find This Useful

Students learning about quadratic inequalities, those seeking to understand factoring methods, and individuals interested in interval testing for inequalities may find this discussion relevant.

mathdad
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Solve the inequality.

x^2 + 4x - 32 < 0

Factor LHS.

(x - 4) (x + 8) < 0

x - 4 = 0

x = 4

x + 8 = 0

x = -8

Plot x = 4 and x = -8 on a number line.

<--------(-8)----------(4)----------->

Pick a number from each interval.

Let x = -10 for (-infinity, -8).

Let x = 0 for (-8, 4).

Let x = 6 for (4, infinity).

Do I avaluate the chosen numbers per interval in the original question or the factored form (x - 4) (x + 8) < 0?
 
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You can look at the signs of each factor to determine the sign of the quadratic in a given interval containing a text value, and so determine if that interval is part of the solution. You really only need to evaluate one interval, and then use the fact that for roots of odd multiplicity, the original expression will change sign across that root, and for roots of even multiplicity, the expression won't change sign.

All of the roots in this problem are of odd multiplicity, so you know the sign of the expression will alternate across all intervals. :D
 
So, it is negative across all three intervals. I will continue later tonight or tomorrow. Going to work now.
 
RTCNTC said:
So, it is negative across all three intervals...

How did you make that determination?
 
I made a typo. The signs alternate across all three intervals. I will complete BOTH inequality questions tomorrow. Look for 5 questions (not math questions) through PM in 15 minutes.
 
Pick a number from each interval.

Let x = -10 for (-infinity, -8).

Let x = 0 for (-8, 4).

Let x = 6 for (4, infinity).

For x = -10, we get False.

For x = 0, we get True.

For x = 6, we get False.

We exclude the end points.

The solution to the original inequality is found in (-8, 4).

Correct?
 
Last edited:
Yes, we have a parabola opening upwards, and given that it has two real roots, we should expect to find it to be negative in between its roots. :D
 
Cool. Two more math questions later tonight.
 

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