High School How Do Jacobi Elliptic Functions Solve Nonlinear Differential Equations?

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SUMMARY

The discussion focuses on solving the nonlinear differential equation ##\frac{d^2x(t)}{dt^2} + B(x(t))^3 = 0## using Jacobi elliptic functions. The user has modeled the system in Python and derived an expression for ##\frac{dx}{dt}##, leading to the integral ##\sqrt{\frac{B}{2}}\int{\frac{1}{\sqrt{x_0^4-x^4}}dx} = \int{dt}##. The suggestion to study Jacobi elliptic functions is made as a method to find a solution, particularly in the context of periodic functions. The discussion emphasizes the importance of initial conditions in determining the constants involved in the solution.

PREREQUISITES
  • Understanding of nonlinear differential equations
  • Familiarity with Jacobi elliptic functions
  • Proficiency in Python for modeling and graphing
  • Knowledge of integral calculus and initial value problems
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  • Study Jacobi elliptic functions and their applications in solving differential equations
  • Learn about perturbation methods and Taylor series expansions for approximating solutions
  • Explore numerical integration techniques for evaluating complex integrals
  • Investigate the use of Python libraries such as SciPy for solving differential equations
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Mathematicians, physicists, and engineers interested in solving nonlinear differential equations, as well as students and researchers working with periodic functions and numerical modeling in Python.

MalachiK
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I have ##\frac{d^2x(t)}{dt^2} + B(x(t))^3 = 0## for a system where I know the initial conditions and where B is a constant that's constructed from the properties of the system. I would like to find ##x(t)##.

I've modeled the system in Python and produced some graphs. I know that ##x(t)## is some periodic function.

Could somebody name the method that I should study so that I can get a solution?
 
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After some further reading I've got this...
Let ##s = x'## so ##s' = x''##

##-Bx^3 = x'' = s' \frac{ds}{dt} = \frac{ds}{dx}\frac{dx}{dt} = \frac{ds}{dx} s##

##-\int{Bx^3 dx} = \int{s ds} ##

##\frac{-Bx^4}{4} + C = \frac{s^2}{2}##

2C is just a constant that I'll rename C

##\sqrt{C-\frac{Bx^4}{2}} = s = \frac{dx}{dt}##

Since ##x(0) = x_0## and ##x'(0) = 0## we have ##C-\frac{Bx_0^4}{2} = 0## so ##C = \frac{Bx_0^4}{2}##

##\frac{dx}{dt} = \sqrt{\frac{B}{2}}\sqrt{x_0^4-x^4}##

##\sqrt{\frac{B}{2}}\int{\frac{1}{\sqrt{x_0^4-x^4}}dx} = \int{dt}##

I don't know if this is correct, but it seems plausible. Now to evaluate the integral.
 
MalachiK said:
I know the initial conditions

Could somebody name the method that I should study so that I can get a solution?
Could you state the initial conditions? I ask because you may be able to perturb the equation, take a naive expansion, and approximating your solution analytically. It would not be exact but the method can be incredibly close (like a truncated Taylor series).
 

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