How Do Response Factors for Na and K Compare Using Li as an Internal Standard?

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SUMMARY

The discussion focuses on determining the response factors for sodium (Na) and potassium (K) using lithium (Li) as an internal standard. The concentration ratio provided is 5.0 ppm for both Na and K, with Li at 500 ppm. The calculated response factors are 13.5 for Na and 17.7 for K, derived from the equations Ax/x = F(As/s). The calculations appear correct based on the provided data, confirming the methodology used in the analysis.

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Homework Statement



Determine the response factors for both Na and K with the Li internal standard

Concentration Ratio
Na : K : Li (in ppm)
5.0 : 5.0: 500
-------------------

Signal Ratio
Na : K : Li (relative units)
4.9 : 6.4: 36.2

Homework Equations



Ax/x = F(As/s)
Ax = absorption signal of analyte
x = concentration of analyte
F = response factor
As = absorption signal of standard
s = concentration of standard

The Attempt at a Solution



Calculation for Na

(4.9)/(5.0) = F [(36.2)/(500)]
F = 13.5

Calculation for K

(6.4)/(5.0) = F [(36.2)/(500)]
F = 17.7

Seems simple enough right? So I was hoping that someone would be able to tell me if this is correct or incorrect because I have a funny feeling I did something strange (problem was too easy).
 
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It would be helpful to have more information on the equation and the reference, but based on the limited information provided, Ax/x = F(As/s), it would appear that the answers given are correct.

Is the problem/question based on an example of chromatography and spectroscopy?
 

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