How Do Spin and Polarization Relate to Photon States?

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SUMMARY

The discussion focuses on the relationship between spin and polarization in photon states, particularly in the context of deriving the Stefan-Boltzmann law. It clarifies that photons have two independent polarization states, which correspond to their helicity states of -1 and +1, while the spin state of 0 is not applicable due to the massless nature of photons. The conclusion emphasizes that the two transverse polarizations are the only allowed states for massless spin-1 particles, as opposed to massive spin-1 particles, which possess three degrees of freedom.

PREREQUISITES
  • Understanding of photon properties, specifically polarization and helicity.
  • Familiarity with the Stefan-Boltzmann law derivation.
  • Knowledge of quantum mechanics concepts, particularly spin and massless particles.
  • Basic grasp of phase space volume elements in statistical mechanics.
NEXT STEPS
  • Study the derivation of the Stefan-Boltzmann law in detail.
  • Explore the concept of helicity in quantum mechanics.
  • Read chapter 6 of "Quarks and Leptons" by Halzen and Martin for deeper insights.
  • Investigate the implications of masslessness on particle spin states.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those interested in the properties of photons, their spin and polarization, and the implications for statistical mechanics and thermodynamics.

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Homework Statement


I'm trying to derive the stefan-Boltzmann law by considering a box of photons (as in Landau and Lifgarbagez and other texts). At one point in the derivation we multiply the density of states by 2 in order to account for the two independent polarizations of a photon. But at what point do we account for the fact that the spin of the photon is 1, so we have the "three" independent spin states, -1, 0, and 1? Or is there a relationship between "spin" and "polarization" that no one told me about?

Homework Equations


The number of states with frequency between w and w+dw is
[tex]2 V d^3w \over (2\pi)^3[/tex]
V is the volume of the box, the rest of the stuff is from the phase space volume element and
the factor 2 out front accounts for the two polarizations.

The Attempt at a Solution


I read an older post about helicity of a photon. The poster mentioned something about a photon not being found in a spin 0 state. I didn't fully understand what he/she was saying. But it made me think that maybe 'polarity' and 'spin' are the same thing for a photon, and that the two polarities just correspond to two of the allowed spins while the third possible spin is just forbidden for some reason.
 
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As far as I understand, what you say is correct..there are three helicity states corresponding to the three spin states of the photon...makes sense since helicity is the projection of the spin along the momentum...and spin projections 1,0 and -1 corresponds to value of projection along, say, the z axis...If you take momentum along the z axis, both helicity and spin should correspond to the same thing...polarizations, on the other hand, are some linear combinations of the helicities...

I think there is some constraint due to masslessness which makes it only two independent helicities (only the transverse ones) for the photon ... a massive spin 1 particle should have 3 degrees of freedom...

Maybe you can look at chapter 6 of the book Quarks and Leptons by Halzen and Martin...
 

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