How Do Tensions in a Massless, Frictionless Pulley System Compare?

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SUMMARY

The discussion focuses on the analysis of tensions in a massless, frictionless pulley system involving a mass M and an applied force F. The equations governing the system are established as T1 - F = 0, T4 - T1 - T3 = 0, T2 + T3 - T5 = 0, and T5 - Mg = 0. It is confirmed that T1, T2, and T3 are equal due to the properties of massless and frictionless pulleys, ensuring that the system remains in equilibrium without infinite angular speed.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of tension in ropes
  • Familiarity with equilibrium conditions in mechanical systems
  • Concept of massless and frictionless pulleys
NEXT STEPS
  • Study the implications of massless and frictionless assumptions in pulley systems
  • Learn about dynamic systems involving multiple pulleys
  • Explore the calculation of forces in static equilibrium
  • Investigate real-world applications of pulley systems in engineering
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Physics students, mechanical engineers, and anyone interested in understanding the mechanics of pulley systems and tension analysis.

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A mass M in held in place by the applied force F and the pulley system shown below. The pulleys are massless and frictionless. Determine the tension in each section in each section of rope and the applied force F

Taking upwards as positve

-T1 - F = 0

T4 - T1 - T3 = 0

T2 + T3 - T5 = 0

T5 - Mg = 0

Now this is where I confused about the tension
To me, I think T1 = T2 = T3
but again, am not sure, can anyone tell me if it was right or wrong ? so I can go on with my problem. Thank you
 

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As the pulleys are massless and frictionless, and T1, T2, T3 are the tensions in the same rope, they must be equal. The massless pulleys would rotate with infinite angular speed otherwise.

ehild
 

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