How Do Two Ladders Hinged Together Maintain Equilibrium?

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SUMMARY

The discussion focuses on the equilibrium of two uniform ladders, AC and BC, hinged at point C, with angles CAB at 60 degrees and CBA at 30 degrees. The primary objectives are to calculate the vertical reactions at points A and B and to determine the force exerted on ladder BC by ladder AC. The solution involves taking moments about points A and B to resolve the vertical reactions, while the force direction is confirmed to be 30 degrees below horizontal. However, the calculation for the force magnitude remains challenging, particularly when considering the moments created by the horizontal forces.

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Homework Statement



Two straight uniform ladders, AC and BC have equal weights. THey stand in equilibrium with their feet, A and b, on rough horizontal ground and their tops freely hinged at C. Angle CAB=60, angle CBA=30 and AB=l.

a)Find the vertical reactions at A and B.
b)Find the magnitude and direction of the force exerted on BC by AC.

Homework Equations



Taking moments about various points, moment=Fd

The Attempt at a Solution



The first part isn't too hard, taking moments about B allows me to resolve the vertical reaction at A, similarly for b.

However, the second part is annoying me. It's clear that the direction of the force is 30degrees below horizontal, however I can't get the value right.
Ignoring the second ladder, taking moments about A, you get a vertical weight force halfway up the ladder which gives a moment which is seen in the perpendicular force at the top of the ladder. But this doesn't give me the correct answer for F, which is W/2
 
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Show your FBD and derivations in detail, please. Why are you sure in the direction of the force between the ladders? Did you count with the moment of the horizontal forces, too?

ehild
 
Last edited:

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