How do we evaluate this sum: \sum_{i=1}^{10}\frac{2i+1}{i^2(i+1)^2}?

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The sum \(\sum_{i=1}^{10}\frac{2i+1}{i^2(i+1)^2}\) was evaluated, with several members providing correct solutions. The key approach involved simplifying the expression and recognizing patterns in the series. Members congratulated for their accurate solutions include hxthanh, Chris L T521, MarkFL, eddybob123, johng, and anemone. The discussion highlighted the importance of understanding series and algebraic manipulation in solving such problems. Overall, the evaluation showcased collaborative problem-solving within the community.
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Evaluate the following sum:

$$\sum_{i=1}^{10}\frac{2i+1}{i^2(i+1)^2}$$
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Congratulations to the following members for their correct solutions:

1) hxthanh
2) Chris L T521
3) MarkFL
4) eddybob123
5) johng
6) anemone

Solution (from hxthanh):
\begin{align*}S_n=\sum_{i=1}^n \dfrac{2i+1}{i^2(i+1)^2}&=\sum_{i=1}^n \dfrac{(i+1)^2-i^2}{i^2(i+1)^2}\\&=\sum_{i=1}^n \left(\dfrac{1}{i^2}-\dfrac{1}{(i+1)^2}\right)\\&=\dfrac{1}{1^2}-\dfrac{1}{(n+1)^2}\end{align*}

With $n=10$, we get: $S_{10}=1-\dfrac{1}{121}=\boxed{\dfrac{120}{121}}$
 

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