How Do You Algebraically Solve for n in Compound Interest Equations?

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Homework Help Overview

The discussion revolves around solving for the variable n in a compound interest equation, specifically in the context of algebraic manipulation and logarithmic application.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants express uncertainty about using logarithms to solve the equation and question whether an analytical solution is feasible. There is mention of numerical techniques as a potential approach.

Discussion Status

Participants are exploring the nuances of the solution, noting that while n=12 is suggested as a solution, it is acknowledged that it may not be exact due to rounding in the given values. The conversation indicates a productive exploration of the problem without reaching a definitive consensus.

Contextual Notes

There is a recognition that the values provided in the equation may be rounded, which affects the precision of the solution for n. Participants are also considering the implications of using approximate versus exact values in their reasoning.

e^(i Pi)+1=0
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Homework Statement


125,000=79,770.26(1+[itex]\frac{.045}{n}[/itex])10n

Homework Equations


The Attempt at a Solution


I'm not sure how to use a logarithm with this, or if it's even possible. I know that n=12, I just don't know how to solve for it.
 
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e^(i Pi)+1=0 said:
I know that n=12, I just don't know how to solve for it.
n = 12 is a solution for sufficiently large values of 12. n=12 (exactly) is not a solution. n≈12.06655246 is a solution.

You can't solve this analytically. You will need to resort to numerical techniques.
 
Thanks, I wasn't sure if I was missing something. It's not exactly 12 here because the 79,770.26 is rounded.
 
79,770.62 is closer, and 79,770.63 is closer still for n=12.
 
D H said:
n = 12 is a solution for sufficiently large values of 12

:smile:
 
D H said:
n = 12 is a solution for sufficiently large values of 12.

Nice! :biggrin:
 

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