MHB How Do You Analyze Particle Motion Along the X-axis Using Calculus?

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The particle's motion along the x-axis is described by the equation s(t) = (1/3)t^3 - t^2 - 8t + 12. To analyze its motion, the velocity and acceleration can be derived using calculus, where velocity v(t) is the first derivative of s(t) and acceleration a(t) is the second derivative. Key time instants for analysis include t = 0 to 6, where the particle's position, velocity, and acceleration can be evaluated. The discussion also addresses when the particle is at rest, in uniform motion, and the intervals of movement direction and acceleration. Understanding these concepts is crucial for a comprehensive analysis of the particle's motion along the x-axis.
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A particle moves along the x-axis according to the equation s(t) = 1/3t^3 -t^2 -8t +12, where s is the directed distance (in meters) of the particle from the origin at time t (in seconds). Find
a. the directed distance of the particle from the origin, its velocity and acceleration at the following time instants: t = 0, 1, 2, 3, 4, 5, 6. Describe the particle’s motion at these time instants.
b. the time instant/s when the particle is instantaneously at rest.
c. the time instant/s when the particle is in uniform motion.
d. the time interval/s when the particle is moving to the right/left.
e. the time interval/s when the particle is accelerating/decelerating.
f.
The trace of the particle’s motion on the x-axis


Hello, I'm having a hard time setting up and solving this problem. any help would be appreciated. Thank you!
 
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Hello and welcome to MHB! (Wave)

We are given:

$$s(t)=\frac{1}{3}t^3-t^2 -8t +12$$

What this tells us is that at time $t$, the particle is located at $s(t)$. Now for velocity $v$ and acceleration $a$ we may use the following definitions:

$$v(t)\equiv\d{s}{t}$$

$$a(t)\equiv\d{v}{t}$$

Using these definitions, can you explicitly state the velocity and acceleration of the particle as functions of $t$?