How Do You Calculate Angle 2 in a Physics Vector Problem?

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Homework Help Overview

The discussion revolves around a physics vector problem involving the calculation of an angle based on given conditions. The original poster seeks clarification on how angle 2 is determined from angle 1, with specific reference to the orientation of vectors and angles in a coordinate system.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between angle 1 and angle 2, with one suggesting the use of parallel lines to aid in visualization. Others explore the geometric relationships between the vectors and angles, noting congruence and perpendicularity.

Discussion Status

The discussion is ongoing, with participants providing insights into the geometric setup and questioning the implications of the angles involved. There is an exploration of different interpretations regarding the orientation of the axes and the vectors.

Contextual Notes

Some participants mention updates to a visual representation of the problem, indicating that the clarity of the diagram may influence the understanding of the angles and vectors involved.

hvidales
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Homework Statement


Homework Equations


The Attempt at a Solution



ivfj8z.jpg


So angle 1 was giving and through that they found angle 2. I need help on how they found angle 2. The dark red arrow is a vector. This is a physics problem asking for something else but I got stuck here lol.

Homework Statement


Homework Equations


The Attempt at a Solution


Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited:
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Add another line parallel to ground intersect x-y origin.
 
The angles are congruent as their arms are pairwise perpendicular. The red vector is vertical, makes a right angle with the horizontal arm of angle 1. The other arm of angle 2 is perpendicular to the slope which is the other arm of angle 1. See picture: β=90-(90-α)=α.

ehild
 

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What happened with the x axis? I updated the picture to look better.


[url=http://postimage.org/][PLAIN]http://s17.postimage.org/h2qbp828v/Untitled.png[/url][/PLAIN]
 

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