How Do You Calculate Equivalent Resistance in Mixed Circuit Configurations?

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huskydc
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How can you separate the series and parallel in this combination?? I'm confused... the question asks for equivalent resistance


I thought it's somelike like this:

1/R eq = 1/2R(1) + 1/R(1) + 1/R(2)

but it's wrong...help?
 
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  • Circuit schematic of resistors: two parallel branches in series, the upper pair both labelled R1, the lower pair labelled R1 and R2, with terminals at top and bottom.
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I can't see the picture, but for resistors in parallel 1/(total resistance) = sum of(1/induvidual resistances)